The weight of 1 times 10^{22} molecules of Cu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 \ g/mol$. $6

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 \ g/mol$. $6.022 	imes 10^{23}$ molecules of $CuSO_4 \cdot 5H_2O$ weigh $249.5 \ g$. Therefore,the weight of $1 	imes 10^{22}$ molecules is: $	ext{Weight} = \frac{249.5 	imes 1 	imes 10^{22}}{6.022 	imes 10^{23}} \ g$. $	ext{Weight} = \frac{249.5}{60.22} \ g \approx 4.143 \ g$. Since $4.143 \ g$ is not exactly $4.159 \ g$,the correct option is $D$.

The weight of $1 \times 10^{22}$ molecules of $CuSO_4 \cdot 5H_2O$ is ........... $g$.

Similar Questions

What is a mole?

What is the numerical value of $\frac{N}{n}$? (Where $N$ is the number of molecules in a given gas sample and $n$ is the number of moles of the gas.)

One atom of an element weighs $3.32 \times 10^{-23} \ g$. How many gram atoms are there in $20 \ kg$ of the element?

Which has the maximum number of molecules among the following?

The number of oxygen atoms in $4.4 \ g$ of $CO_2$ is approximately ........ $\times 10^{23}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module