There are two urns. Urn A has 3 distinct red | vedclass

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(C) Urn $A$ contains $3$ distinct red balls. The number of ways to select $2$ balls from urn $A$ is $^3C_2 = \frac{3!}{2!1!} = 3$.Urn $B$ contains $9$

Vedclass · Accepted Answer

$108$

Vedclass · Answer

(C) Urn $A$ contains $3$ distinct red balls. The number of ways to select $2$ balls from urn $A$ is $^3C_2 = \frac{3!}{2!1!} = 3$.Urn $B$ contains $9$ distinct blue balls. The number of ways to select $2$ balls from urn $B$ is $^9C_2 = \frac{9 	imes 8}{2 	imes 1} = 36$.Since the selection of balls from urn $A$ and urn $B$ are independent events,the total number of ways to perform these transfers is the product of the number of ways to select balls from each urn.Total ways $= ^3C_2 	imes ^9C_2 = 3 	imes 36 = 108$.

There are two urns. Urn $A$ has $3$ distinct red balls and urn $B$ has $9$ distinct blue balls. From each urn,two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

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