There is a $5\,\Omega$ resistance in an $AC$ circuit. An inductance of $0.1\,H$ is connected in series with it. If the equation of the $AC$ $EMF$ is $E = 5\sin(50t)$,then the phase difference between the current and the $EMF$ is:

  • A
    $\frac{\pi}{2}$
  • B
    $\frac{\pi}{6}$
  • C
    $\frac{\pi}{4}$
  • D
    $0$

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