Three 6-faced dice are thrown together. The p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total number of possible outcomes when three $6$-faced dice are thrown is $6^3 = 216$.The number of favorable outcomes where all three dice sh

Vedclass · Accepted Answer

$\frac{1}{36}$

Vedclass · Answer

(B) The total number of possible outcomes when three $6$-faced dice are thrown is $6^3 = 216$.The number of favorable outcomes where all three dice show the same number is $6$,which are: ${(1,1,1), (2,2,2), (3,3,3), (4,4,4), (5,5,5), (6,6,6)}$.Therefore,the required probability is $\frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{6}{216} = \frac{1}{36}$.

Three $6$-faced dice are thrown together. The probability that all the three show the same number on them is:

Similar Questions

Tickets numbered $1$ to $20$ are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of $3$ or $5$?

When two dice are rolled,what is the probability that the sum of the numbers appearing is a multiple of $3$?

For two events $A$ and $B$,if $P(A) = P(A|B) = \frac{1}{4}$ and $P(B|A) = \frac{1}{2}$,then

Two cards are drawn from a well-shuffled ordinary deck of $52$ cards. What is the probability that they are both aces if the first card is not replaced?

If $P(A) = 2/3$,$P(B) = 1/2$ and $P(A \cup B) = 5/6$,then events $A$ and $B$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module