Three $6$-faced dice are thrown together. The probability that no two dice show the same number on them is

  • A
    $\frac{7}{12}$
  • B
    $\frac{5}{9}$
  • C
    $\frac{1}{36}$
  • D
    $\frac{5}{12}$

Explore More

Similar Questions

$A$ bag $x$ contains $3$ white balls and $2$ black balls and another bag $y$ contains $2$ white balls and $4$ black balls. $A$ bag and a ball out of it are picked at random. The probability that the ball is white,is

In order to get at least one head with a probability $\ge 0.9$,the minimum number of times a coin needs to be tossed is:

Difficult
View Solution

$2$ dice are thrown. Find the probability of getting a doublet of even numbers.

In a box,there are $8$ red,$7$ blue and $6$ green balls. One ball is picked up at random. What is the probability that it is neither red nor green?

If $P(A) = 2/3$,$P(B) = 1/2$ and $P(A \cup B) = 5/6$,then events $A$ and $B$ are

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo