Three capacitances of capacity $10\,\mu F$,$5\,\mu F$,and $5\,\mu F$ are connected in parallel. The total capacity will be ........ $\mu F$.

$A$ $5 \mu F$ capacitor is connected in series with a $10 \mu F$ capacitor. When a $300 \ V$ potential difference is applied across this combination, the total energy stored in the capacitors is (in $J$)

Find the equivalent capacitance between point $A$ and $B$. (in $C$)

In the following circuit,the resultant capacitance between $A$ and $B$ is $1\,\mu F$. Then the value of $C$ is

Four capacitors of equal capacity have an equivalent capacitance $C_{1}$ when connected in series and an equivalent capacitance $C_{2}$ when connected in parallel. The ratio $\frac{C_{2}}{C_{1}}$ is:

Three capacitors $2\,\mu F$,$3\,\mu F$,and $6\,\mu F$ are joined in series with each other. What is the minimum effective capacitance in $\mu F$?