Three complexes,[CoCl(NH_3)_5]^{2+} (I),[Co(N | vedclass

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(C) The energy of absorbed light $(E)$ is inversely proportional to the wavelength $(\lambda)$ of the absorbed light,i.e.,$E = \frac{hc}{\lambda}$.The

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$I > II > III$

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(C) The energy of absorbed light $(E)$ is inversely proportional to the wavelength $(\lambda)$ of the absorbed light,i.e.,$E = \frac{hc}{\lambda}$.The energy of absorption corresponds to the Crystal Field Splitting Energy ($CFSE$ or $\Delta_o$),which depends on the strength of the ligands.The spectrochemical series order for the ligands is $Cl^- Comparing the complexes:$(I) [CoCl(NH_3)_5]^{2 }$ has $Cl^-$ as a ligand.$(II) [Co(NH_3)_5H_2O]^{3 }$ has $H_2O$ as a ligand.$(III) [Co(NH_3)_6]^{3 }$ has $NH_3$ as a ligand.Since $NH_3$ is a stronger ligand than $H_2O$,and $H_2O$ is stronger than $Cl^-$,the order of $CFSE$ is $(III) > (II) > (I)$.Since $E \propto \Delta_o$,the order of energy absorbed is $(III) > (II) > (I)$.Since $\lambda \propto \frac{1}{E}$,the order of wavelength absorbed is $(I) > (II) > (III)$.

List-$I$ (Coordination entity)	List-$II$ (Wavelength of light absorbed in $nm$)
$A$. $[CoCl(NH_3)_5]^{2+}$	$I$. $310$
$B$. $[Co(NH_3)_6]^{3+}$	$II$. $475$
$C$. $[Co(CN)_6]^{3-}$	$III$. $535$
$D$. $[Cu(H_2O)_4]^{2+}$	$IV$. $600$

Three complexes,$[CoCl(NH_3)_5]^{2+} (I)$,$[Co(NH_3)_5H_2O]^{3+} (II)$ and $[Co(NH_3)_6]^{3+} (III)$ absorb light in the visible region. The correct order of the wavelength of light absorbed by them is

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Which of the following comparisons is correct for the crystal field splitting energy $\Delta_0$ of the following complexes?
$I$- $[Co(H_2O)_6]^{2+}$
$II$- $[Co(H_2O)_6]^{3+}$
$III$- $[Fe(H_2O)_6]^{3+}$
$IV$- $[Fe(CN)_6]^{3+}$

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