Three equal cubes are placed adjacently in a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the edge of each cube be $a$.When three such cubes are placed adjacently in a row,they form a cuboid.The dimensions of this new cuboid are: Le

Vedclass · Accepted Answer

$7:9$

Vedclass · Answer

(A) Let the edge of each cube be $a$.When three such cubes are placed adjacently in a row,they form a cuboid.The dimensions of this new cuboid are: Length $(l) = 3a$,Breadth $(b) = a$,and Height $(h) = a$.The total surface area of the new cuboid is given by the formula $2(lb + bh + lh)$.Substituting the values: $2(3a 	imes a + a 	imes a + 3a 	imes a) = 2(3a^2 + a^2 + 3a^2) = 2(7a^2) = 14a^2$.The surface area of one cube is $6a^2$. Therefore,the sum of the surface areas of the three cubes is $3 	imes 6a^2 = 18a^2$.The required ratio is $\frac{14a^2}{18a^2} = \frac{7}{9}$,which is $7:9$.

Three equal cubes are placed adjacently in a row. Find the ratio of the total surface area of the new cuboid to the sum of the surface areas of the three cubes.

Similar Questions

In $\Delta ABC$,$AD$ and $AE$ are bisectors of $\angle BAC$ and $\angle BAD$ respectively. If $\angle BAE = 30^{\circ}$,$AE = 9 \text{ cm}$,and $EC = 15 \text{ cm}$,what is the area (in $\text{cm}^2$) of $\Delta AEC$?

If the base of a parallelogram is $(x+4)$,the altitude to the base is $(x-3)$,and the area is $(x^{2}-4)$,then the actual area is equal to (in $Sq\, units$)

The area of a triangular lawn is $1600 \, m^{2}$. If one side is $64 \, m$ long and the other two sides are equal in length,the length of each equal side is......$m$

If a square is inscribed in a circle,the ratio of the area of the circle and the square is

If the radius of a circle is increased by $75 \%,$ then its circumference will increase by (in $\%$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module