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(C) To find the minimum distance that all three men can cover in complete steps,we need to calculate the Least Common Multiple $(LCM)$ of their step l

Vedclass · Accepted Answer

$6930$

Vedclass · Answer

(C) To find the minimum distance that all three men can cover in complete steps,we need to calculate the Least Common Multiple $(LCM)$ of their step lengths: $63 \, cm$,$70 \, cm$,and $77 \, cm$.Step $1$: Prime factorization of the numbers:$63 = 3^2 	imes 7$$70 = 2 	imes 5 	imes 7$$77 = 7 	imes 11$Step $2$: Calculate the $LCM$ by taking the highest power of each prime factor present:$LCM = 2^1 	imes 3^2 	imes 5^1 	imes 7^1 	imes 11^1$$LCM = 2 	imes 9 	imes 5 	imes 7 	imes 11$$LCM = 10 	imes 9 	imes 77$$LCM = 90 	imes 77 = 6930$Therefore,the minimum distance is $6930 \, cm$.

Three men step off together from the same spot. Their steps measure $63 \, cm$,$70 \, cm$,and $77 \, cm$ respectively. The minimum distance each should cover so that all can cover the distance in complete steps is (in $cm$):

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