Three particles,each having a charge of 10,mu | vedclass

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(C) The electrostatic potential energy of a system of point charges is given by the sum of the potential energies of all distinct pairs of charges: $U

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$27$

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(C) The electrostatic potential energy of a system of point charges is given by the sum of the potential energies of all distinct pairs of charges: $U = \sum \frac{1}{4\pi\varepsilon_0} \frac{q_i q_j}{r_{ij}}$.For an equilateral triangle with three identical charges $q = 10\,\mu C = 10^{-5}\,C$ and side length $r = 10\,cm = 0.1\,m$,there are three identical pairs.$U_{system} = 3 	imes \left( \frac{1}{4\pi\varepsilon_0} \frac{q^2}{r} ight)$.Substituting the values: $U_{system} = 3 	imes (9 	imes 10^9) 	imes \frac{(10^{-5})^2}{0.1}$.$U_{system} = 27 	imes 10^9 	imes \frac{10^{-10}}{0.1} = 27 	imes 10^9 	imes 10^{-9} = 27\,J$.

Three particles,each having a charge of $10\,\mu C$,are placed at the corners of an equilateral triangle of side $10\,cm$. The electrostatic potential energy of the system is.....$J$ (Given $\frac{1}{4\pi\varepsilon_0} = 9 \times 10^9\,N\cdot m^2/C^2$).

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