Three particles,each having a charge of 10 mu | vedclass

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(C) The electrostatic potential energy $U$ of a system of point charges is given by the sum of the potential energies of all distinct pairs of charges

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$27 \ J$

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(C) The electrostatic potential energy $U$ of a system of point charges is given by the sum of the potential energies of all distinct pairs of charges: $U = \sum \frac{1}{4 \pi \varepsilon_{0}} \frac{q_{i} q_{j}}{r_{ij}}$.For an equilateral triangle with three identical charges $q = 10 \mu C = 10 	imes 10^{-6} \ C$ and side length $r = 10 \ cm = 0.1 \ m$,there are three identical pairs.$U_{	ext{system}} = 3 	imes \left( \frac{1}{4 \pi \varepsilon_{0}} \frac{q^{2}}{r} ight)$.Substituting the values:$U_{	ext{system}} = 3 	imes (9 	imes 10^{9}) 	imes \frac{(10 	imes 10^{-6})^{2}}{0.1}$.$U_{	ext{system}} = 27 	imes 10^{9} 	imes \frac{100 	imes 10^{-12}}{0.1}$.$U_{	ext{system}} = 27 	imes 10^{9} 	imes 1000 	imes 10^{-12}$.$U_{	ext{system}} = 27 	imes 10^{12} 	imes 10^{-12} = 27 \ J$.

Three particles,each having a charge of $10 \mu C$,are placed at the corners of an equilateral triangle of side $10 \ cm$. The electrostatic potential energy of the system is (Given $\frac{1}{4 \pi \varepsilon_{0}} = 9 \times 10^{9} \ N \cdot m^{2}/C^{2}$):

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