Through a narrow slit of width 2 ,mm, a diffr | vedclass

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(B) The distance between the two first-order minima on either side of the central maximum is equal to the width of the central maximum.The formula for

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$1.27$

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(B) The distance between the two first-order minima on either side of the central maximum is equal to the width of the central maximum.The formula for the width of the central maximum in a single-slit diffraction pattern is given by $w = \frac{2 \lambda D}{a}$.Given values are:Slit width $a = 2 \,mm = 2 	imes 10^{-3} \,m$Distance to screen $D = 2 \,m$Wavelength $\lambda = 6330 \mathring{A} = 6330 	imes 10^{-10} \,m$Substituting these values into the formula:$w = \frac{2 	imes 6330 	imes 10^{-10} 	imes 2}{2 	imes 10^{-3}}$$w = 2 	imes 6330 	imes 10^{-7} \,m$$w = 12660 	imes 10^{-7} \,m = 1.266 	imes 10^{-3} \,m$$w \approx 1.27 \,mm$.

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