To draw a pair of tangents to a circle which | vedclass

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(B) Let the angle between the two tangents be $	heta = 35^{\circ}.$In the quadrilateral formed by the center of the circle,the two points of contact,

Vedclass · Accepted Answer

$145$

Vedclass · Answer

(B) Let the angle between the two tangents be $	heta = 35^{\circ}.$In the quadrilateral formed by the center of the circle,the two points of contact,and the intersection point of the tangents,the angles at the points of contact are $90^{\circ}$ each (since the radius is perpendicular to the tangent).Thus,the sum of the angles in the quadrilateral is $360^{\circ}.$Let the angle between the radii be $\alpha.$Then,$\alpha + 90^{\circ} + 	heta + 90^{\circ} = 360^{\circ}.$$\alpha + 	heta = 180^{\circ}.$$\alpha = 180^{\circ} - 35^{\circ} = 145^{\circ}.$

To draw a pair of tangents to a circle which are inclined to each other at an angle of $35^{\circ},$ it is required to draw tangents at the end points of those two radii of the circle,the angle between which is (in $^{\circ}$)

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