Total number of spectral lines when an electr | vedclass

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(C) Given: $n_2 = 8$ and $n_1 = 2$.The total number of spectral lines emitted when an electron transitions from a higher energy level $n_2$ to a lower

Vedclass · Accepted Answer

$21$

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(C) Given: $n_2 = 8$ and $n_1 = 2$.The total number of spectral lines emitted when an electron transitions from a higher energy level $n_2$ to a lower energy level $n_1$ is calculated using the formula:$N = \frac{(n_2 - n_1)(n_2 - n_1 + 1)}{2}$Substituting the values:$N = \frac{(8 - 2)(8 - 2 + 1)}{2}$$N = \frac{6 	imes 7}{2}$$N = \frac{42}{2}$$N = 21$Thus,the total number of spectral lines is $21$.

Total number of spectral lines when an electron jumps from the $8^{th}$ orbit to the $2^{nd}$ orbit is:

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