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Question

(B) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $n = 6 	imes 6 = 36$.The favorable outcomes for the sum

Vedclass · Accepted Answer

$\frac{1}{6}$

Vedclass · Answer

(B) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $n = 6 	imes 6 = 36$.The favorable outcomes for the sum of the numbers on the dice to be $7$ are: $(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)$.Thus,the number of favorable outcomes is $m = 6$.The probability of the event is given by the formula: $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{m}{n}$.Substituting the values,we get: $P(E) = \frac{6}{36} = \frac{1}{6}$.

Two balanced dice are rolled simultaneously. Then,the probability that the sum of numbers on the dice is $7$ is ............

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