Two balls A and B having masses 1, kg and 2, | vedclass

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(D) Using the Law of Conservation of Linear Momentum:$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$Taking the direction of $A$ as positive: $1(21) + 2(-4) =

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(D) Using the Law of Conservation of Linear Momentum:$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$Taking the direction of $A$ as positive: $1(21) + 2(-4) = 1(1) + 2 v_2$$21 - 8 = 1 + 2 v_2 \Rightarrow 13 = 1 + 2 v_2 \Rightarrow 2 v_2 = 12 \Rightarrow v_2 = 6\, m/s$.Since $v_2$ is positive,$B$ moves in the original direction of $A$,which is opposite to its initial direction.Coefficient of Restitution $(e)$:$e = \frac{v_2 - v_1}{u_1 - u_2} = \frac{6 - 1}{21 - (-4)} = \frac{5}{25} = 0.2$.Loss of Kinetic Energy $(\Delta K)$:$\Delta K = K_i - K_f = [\frac{1}{2} m_1 u_1^2 + \frac{1}{2} m_2 u_2^2] - [\frac{1}{2} m_1 v_1^2 + \frac{1}{2} m_2 v_2^2]$$K_i = \frac{1}{2}(1)(21^2) + \frac{1}{2}(2)(4^2) = 220.5 + 16 = 236.5\, J$.$K_f = \frac{1}{2}(1)(1^2) + \frac{1}{2}(2)(6^2) = 0.5 + 36 = 36.5\, J$.$\Delta K = 236.5 - 36.5 = 200\, J$.

Two balls $A$ and $B$ having masses $1\, kg$ and $2\, kg$,moving with speeds $21\, m/s$ and $4\, m/s$ respectively in opposite directions,collide head-on. After the collision,$A$ moves with a speed of $1\, m/s$ in the same direction. Which of the following statements is correct?

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