Two blocks of masses m and 2m are connected b | vedclass

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(D) The system consists of two masses $m$ and $2m$ connected by a string over a pulley. The acceleration $a$ of the system is given by $a = \frac{(m_2

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$\frac{4mg}{3A}$

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(D) The system consists of two masses $m$ and $2m$ connected by a string over a pulley. The acceleration $a$ of the system is given by $a = \frac{(m_2 - m_1)g}{m_1 + m_2}$.Substituting the values,$a = \frac{(2m - m)g}{2m + m} = \frac{mg}{3m} = \frac{g}{3}$.The tension $T$ in the wire can be found using the equation of motion for mass $m$: $T - mg = ma$,so $T = m(g + a)$.Substituting $a = \frac{g}{3}$,we get $T = m(g + \frac{g}{3}) = m(\frac{4g}{3}) = \frac{4mg}{3}$.Stress is defined as force per unit area,so $	ext{Stress} = \frac{T}{A} = \frac{4mg}{3A}$.

Two blocks of masses $m$ and $2m$ are connected by a metal wire of negligible mass and having cross-sectional area $A$,passing over a smooth fixed pulley as shown in the figure. If the masses are released from rest,then the stress produced in the wire is:

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