Two identical blocks each of mass $M$ are attached to the ends of a massless inextensible string which passes over a pulley with a fixed axis as shown below. $A$ small mass $m$ is now placed on block $B$ (the right block). The acceleration with which the two blocks move together is ($g =$ gravitational acceleration).

$A$ block of mass $m$ is pulled by a force of $40 \, N$ on a smooth horizontal surface as shown in the figure. The tension at the middle of the block is ........... $N$.

The ends of a rope are held by two men who pull on it with equal and opposite forces of magnitude $F$ each. Then the tension in the rope is

$A$ light unstretchable string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$. If the acceleration of the system is $\frac{g}{8}$,then the ratio of the masses $\frac{m_2}{m_1}$ is:

Consider a body of mass $3\,kg$ at rest on a smooth horizontal table. This body is connected by a light string,which passes over a smooth pulley at the edge of the table,to another body of mass $2\,kg$ hanging freely. This $2\,kg$ mass is released from rest. Now consider the following statements:
$(A)$ The masses remain at rest.
$(B)$ The $3\,kg$ mass moves uniformly while the $2\,kg$ mass moves with acceleration $\frac{2}{5}g\,m/s^2$.
$(C)$ Both bodies move with acceleration $\frac{2}{5}g\,m/s^2$.
$(D)$ The tension in the string near the first body is more than that near the second body.
$(E)$ The tension in the string is $\frac{6g}{5}\,N$.
Then the correct statements are:

$A$ uniform chain of length $2L$ is hanging in an equilibrium position. If end $B$ is given a slightly downward displacement,the imbalance causes an acceleration. Here,the pulley is small and smooth,and the string is inextensible. Find the velocity $v$ of the chain when it slips out of the pulley (height of pulley from floor $> 2L$).