Two bodies of masses m_1 and m_2 have equal k | vedclass

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(C) The kinetic energy $E$ of a body of mass $m$ and momentum $p$ is given by the relation $E = \frac{p^2}{2m}$.Rearranging this formula,we get $p = \

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$\sqrt{m_1}:\sqrt{m_2}$

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(C) The kinetic energy $E$ of a body of mass $m$ and momentum $p$ is given by the relation $E = \frac{p^2}{2m}$.Rearranging this formula,we get $p = \sqrt{2mE}$.Since the kinetic energies of the two bodies are equal $(E_1 = E_2 = E)$,the momentum $p$ is directly proportional to the square root of the mass: $p \propto \sqrt{m}$.Therefore,the ratio of their momenta is $\frac{p_1}{p_2} = \sqrt{\frac{m_1}{m_2}}$.Thus,the ratio $p_1:p_2$ is $\sqrt{m_1}:\sqrt{m_2}$.

Two bodies of masses $m_1$ and $m_2$ have equal kinetic energies. If $p_1$ and $p_2$ are their respective momenta,then the ratio $p_1:p_2$ is equal to

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