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(A) When the pulley moves upward with an acceleration $a_p = \frac{g}{2}$,we can analyze the motion of the masses $m_1$ and $m_2$ from the non-inertia

Vedclass · Accepted Answer

$\frac{3 m_1 m_2}{m_1+m_2} g$

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(A) When the pulley moves upward with an acceleration $a_p = \frac{g}{2}$,we can analyze the motion of the masses $m_1$ and $m_2$ from the non-inertial frame of reference of the pulley. In this frame,a pseudo force $F_p = m \cdot a_p$ acts on each mass in the downward direction.The effective acceleration due to gravity in the pulley's frame is $g_{eff} = g + a_p = g + \frac{g}{2} = \frac{3g}{2}$.The tension $T$ in a string connecting two masses $m_1$ and $m_2$ over a pulley is given by the formula $T = \frac{2 m_1 m_2}{m_1 + m_2} g_{eff}$.Substituting $g_{eff} = \frac{3g}{2}$ into the formula:$T = \frac{2 m_1 m_2}{m_1 + m_2} \left( \frac{3g}{2} \right)$$T = \frac{3 m_1 m_2}{m_1 + m_2} g$.

Two bodies of masses $m_1$ and $m_2$ are connected by a light string which passes over a frictionless,massless pulley. If the pulley is moving upward with uniform acceleration $\frac{g}{2}$,then the tension in the string will be .........

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