Two brands of chocolates are available in pac | vedclass

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(A) To find the least number of chocolates that are equal for both brands,we need to calculate the Least Common Multiple $(LCM)$ of $24$ and $15$.Prim

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$5$ boxes of the first kind and $8$ boxes of the second kind

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(A) To find the least number of chocolates that are equal for both brands,we need to calculate the Least Common Multiple $(LCM)$ of $24$ and $15$.Prime factorization of $24 = 2^3 	imes 3^1$.Prime factorization of $15 = 3^1 	imes 5^1$.$LCM(24, 15) = 2^3 	imes 3^1 	imes 5^1 = 8 	imes 3 	imes 5 = 120$.To find the number of boxes for the first brand ($24$ chocolates per pack): $120 / 24 = 5$ boxes.To find the number of boxes for the second brand ($15$ chocolates per pack): $120 / 15 = 8$ boxes.Therefore,one needs to buy $5$ boxes of the first kind and $8$ boxes of the second kind.

Two brands of chocolates are available in packs of $24$ and $15$ respectively. If one needs to buy an equal number of chocolates of both kinds,what is the least number of boxes of each kind would one need to buy?

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