Two capacitors C_1 and C_2 = 2C_1 are connect | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the steady state,the current in the circuit becomes zero,and both capacitors are connected in parallel across the same potential difference. Le

Vedclass · Accepted Answer

$\frac{Q}{3}, \frac{2Q}{3}$

Vedclass · Answer

(B) In the steady state,the current in the circuit becomes zero,and both capacitors are connected in parallel across the same potential difference. Let the new charges on $C_1$ and $C_2$ be $Q_1$ and $Q_2$ respectively.Since they are in parallel,their potentials must be equal:$V_1 = V_2 \implies \frac{Q_1}{C_1} = \frac{Q_2}{C_2}$Given $C_2 = 2C_1$,we have:$\frac{Q_1}{C_1} = \frac{Q_2}{2C_1} \implies Q_2 = 2Q_1$According to the law of conservation of charge,the total charge remains constant:$Q_1 + Q_2 = Q$Substituting $Q_2 = 2Q_1$ into the conservation equation:$Q_1 + 2Q_1 = Q \implies 3Q_1 = Q \implies Q_1 = \frac{Q}{3}$Then,$Q_2 = 2Q_1 = \frac{2Q}{3}$Thus,the charges on the capacitors are $\frac{Q}{3}$ and $\frac{2Q}{3}$.

Two capacitors $C_1$ and $C_2 = 2C_1$ are connected in a circuit with a switch and a resistor as shown in the figure. Initially,the switch is open and $C_1$ holds charge $Q$. The switch is closed. At steady state,the charge on each capacitor will be:

Similar Questions

Two capacitors of capacitance $3 \ \mu F$ and $6 \ \mu F$ are charged to a potential of $12 \ V$. They are then connected by joining their positive plates together and their negative plates together. What will be the potential difference across each capacitor in $V$?

$A$ $2\,\mu F$ capacitor has a potential difference of $200\;V$ across its terminals. It is disconnected from the battery and then another uncharged capacitor is connected in parallel to it. If the potential difference becomes $20\;V$,the capacitance of the second capacitor is.......$\mu F$.

$A$ capacitor of capacitance $C_1 = 10 \mu F$ is charged using a $9 \text{ V}$ battery. It is then removed from the battery and connected to another uncharged capacitor $C_2 = 20 \mu F$ as shown in the figure. The charge on $C_2$ after equilibrium is reached is:

When two isolated conductors $A$ and $B$ are connected by a conducting wire,positive charge will flow from:

Vedclass Test Series

Exam Paper Generator

Online Exam Module