Two charged identical metal spheres A and B r | vedclass

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(B) Let the initial charges on spheres $A$ and $B$ be $q$. The distance between them is $r$.The initial repulsive force is $F = \frac{k q^2}{r^2} = 3

Vedclass · Accepted Answer

$3 	imes 10^{-5} \,N$

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(B) Let the initial charges on spheres $A$ and $B$ be $q$. The distance between them is $r$.The initial repulsive force is $F = \frac{k q^2}{r^2} = 3 	imes 10^{-5} \,N$.When uncharged sphere $C$ touches sphere $A$, the charge $q$ is shared equally between $A$ and $C$. Thus, the charge on $A$ becomes $q/2$ and the charge on $C$ becomes $q/2$.Sphere $C$ is then placed at the midpoint between $A$ and $B$. The distance of $C$ from both $A$ and $B$ is $r/2$.The force exerted by $A$ on $C$ is $F_{AC} = \frac{k (q/2)(q/2)}{(r/2)^2} = \frac{k q^2}{r^2} = F = 3 	imes 10^{-5} \,N$ (repulsive, directed towards $B$).The force exerted by $B$ on $C$ is $F_{BC} = \frac{k (q)(q/2)}{(r/2)^2} = 2 \frac{k q^2}{r^2} = 2F = 6 	imes 10^{-5} \,N$ (repulsive, directed towards $A$).The net force on $C$ is $F' = |F_{BC} - F_{AC}| = |2F - F| = F = 3 	imes 10^{-5} \,N$.

Two charged identical metal spheres $A$ and $B$ repel each other with a force of $3 \times 10^{-5} \,N$. Another identical uncharged sphere $C$ is touched with sphere $A$ and then it is placed mid-way between $A$ and $B$. Then, the magnitude of net force on $C$ is

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