Two concentric coils each of radius equal to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field at the centre of a circular coil is given by $B = \frac{\mu_0 I}{2a}$,where $a$ is the radius.Given $a = 2\pi 	ext{ cm} = 2\pi

Vedclass · Accepted Answer

$5 	imes 10^{-5}$

Vedclass · Answer

(C) The magnetic field at the centre of a circular coil is given by $B = \frac{\mu_0 I}{2a}$,where $a$ is the radius.Given $a = 2\pi 	ext{ cm} = 2\pi 	imes 10^{-2} 	ext{ m}$.For the first coil with current $I_1 = 3 	ext{ A}$:$B_1 = \frac{\mu_0 	imes 3}{2 	imes 2\pi 	imes 10^{-2}} = \frac{4\pi 	imes 10^{-7} 	imes 3}{4\pi 	imes 10^{-2}} = 3 	imes 10^{-5} 	ext{ T}$.For the second coil with current $I_2 = 4 	ext{ A}$:$B_2 = \frac{\mu_0 	imes 4}{2 	imes 2\pi 	imes 10^{-2}} = \frac{4\pi 	imes 10^{-7} 	imes 4}{4\pi 	imes 10^{-2}} = 4 	imes 10^{-5} 	ext{ T}$.Since the coils are placed at right angles,the resultant magnetic field is $B = \sqrt{B_1^2 + B_2^2}$.$B = \sqrt{(3 	imes 10^{-5})^2 + (4 	imes 10^{-5})^2} = \sqrt{9 	imes 10^{-10} + 16 	imes 10^{-10}} = \sqrt{25 	imes 10^{-10}} = 5 	imes 10^{-5} 	ext{ T}$.

Two concentric coils each of radius equal to $2\pi \text{ cm}$ are placed at right angles to each other. If $3 \text{ A}$ and $4 \text{ A}$ are the currents flowing through the two coils respectively,the magnetic induction (in $\text{Wb m}^{-2}$) at the centre of the coils will be:

Similar Questions

The direction of magnetic lines of force close to a straight conductor carrying current will be

$A$ part of a long wire carrying a current $i$ is bent into a circle of radius $r$ as shown in the figure. The net magnetic field at the centre $O$ of the circular loop is

$A$ long straight wire of radius $a$ carries a steady current $I$. The current is uniformly distributed across its cross-section. The ratio of the magnetic field at $\frac{a}{2}$ and $2a$ from the axis of the wire is:

$A$ wire in the form of a circular loop of one turn carrying a current produces a magnetic field $B$ at the centre. If the same wire is looped into a coil of two turns and carries the same current,the new value of magnetic induction at the centre is

Current $i$ is passed through a circular arc as shown in the diagram. If the radius of the circle is $R$,then the magnetic flux density at the centre $P$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module