Two concentric hollow spherical conductors of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electric potential $V$ at a point due to a spherical shell is given by:$1$. Inside the shell $(r < 	ext{radius})$: $V = \frac{KQ}{	ext{radiu

Vedclass · Accepted Answer

$\frac{KQ}{6R}$

Vedclass · Answer

(A) The electric potential $V$ at a point due to a spherical shell is given by:$1$. Inside the shell $(r $2$. Outside the shell $(r > 	ext{radius})$: $V = \frac{KQ}{r}$For a point at $r = \frac{3R}{2}$:- This point is outside the inner shell (radius $R$), so the potential due to the inner shell is $V_1 = \frac{KQ}{3R/2} = \frac{2KQ}{3R}$.- This point is inside the outer shell (radius $2R$), so the potential due to the outer shell is $V_2 = \frac{K(-Q)}{2R} = -\frac{KQ}{2R}$.The total potential $V$ is the sum of the potentials due to both shells:$V = V_1 + V_2 = \frac{2KQ}{3R} - \frac{KQ}{2R}$$V = \frac{4KQ - 3KQ}{6R} = \frac{KQ}{6R}$

Two concentric hollow spherical conductors of radii $R$ and $2R$ have charges $Q$ and $-Q$ respectively. Find the electric potential at a distance of $\frac{3R}{2}$ from the centre. $\left[K=\frac{1}{4\pi\varepsilon_0}\right]$

Similar Questions

$A$ charge of $10 \, \text{esu}$ is placed at a distance of $2 \, \text{cm}$ from a charge of $40 \, \text{esu}$ and at a distance of $4 \, \text{cm}$ from another charge of $-20 \, \text{esu}$. The potential energy of the $10 \, \text{esu}$ charge in ergs is:

Four point charges are placed at the vertices of a square of side $2.8 \,m$ as shown in the figure. Find the electric potential at the centre of the square. (in $\,V$)

Three charges,each $+q$,are placed at the corners of an isosceles triangle $ABC$ with sides $BC = AC = 2a$. $D$ and $E$ are the midpoints of $BC$ and $AC$,respectively. The work done in taking a charge $Q$ from $D$ to $E$ is

$A$ conducting sphere of radius $R$ is given a charge $Q$. The electric potential and the electric field at the centre of the sphere respectively are

Four electric charges $+q, +q, -q$ and $-q$ are placed in order at the corners of a square of side $2L$. The electric potential at point $P$,which is midway between the two positive charges,is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module