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(A) When two elements $P$ and $Q$ are connected in series,the current $i$ flowing through both is the same,while the total potential difference $V$ ac

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(A) When two elements $P$ and $Q$ are connected in series,the current $i$ flowing through both is the same,while the total potential difference $V$ across the combination is the sum of the potential differences across each element: $V = V_P + V_Q$.From the given graphs:For element $P$: $i$ increases linearly with $V_P$ up to $10 \ V$ (where $i = 1 \ A$),and then $i$ remains constant at $1 \ A$ for $V_P > 10 \ V$.For element $Q$: $i$ increases non-linearly with $V_Q$ up to $10 \ V$ (where $i = 1 \ A$),and then $i$ remains constant at $1 \ A$ for $V_Q > 10 \ V$.For the series combination:$1$. When $i $2$. When $i = 1 \ A$: Both elements reach their saturation current of $1 \ A$. At this point,$V_P = 10 \ V$ and $V_Q = 10 \ V$,so $V = 10 + 10 = 20 \ V$.$3$. When $i > 1 \ A$: Neither element can conduct more than $1 \ A$ of current. Thus,the series combination cannot conduct more than $1 \ A$ of current. The current remains constant at $1 \ A$ for any $V > 20 \ V$.Comparing this with the given options,Graph $A$ shows the current $i$ increasing with $V$ up to $20 \ V$ and then remaining constant at $1 \ A$ for $V > 20 \ V$.

Two current elements $P$ and $Q$ have current-voltage characteristics as shown below:
Which of the graphs given below represents the current-voltage characteristics when $P$ and $Q$ are in series?

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Two current elements $P$ and $Q$ have current-voltage characteristics as shown below:Which of the graphs given below represents the current-voltage characteristics when $P$ and $Q$ are in series?