Two electric bulbs A and B are rated as 60, W | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage.Since both bulbs are connected in parallel to the same s

Vedclass · Accepted Answer

$B$ draws more current than $A$

Vedclass · Answer

(C) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage.Since both bulbs are connected in parallel to the same source,the voltage $V$ across each bulb is the same.From the relation $P = \frac{V^2}{R}$,we have $R = \frac{V^2}{P}$.For bulb $A$,$P_A = 60\, W$,so $R_A = \frac{V^2}{60}$.For bulb $B$,$P_B = 100\, W$,so $R_B = \frac{V^2}{100}$.The current drawn by a bulb is given by $I = \frac{V}{R}$.Substituting $R$,we get $I = \frac{V}{V^2/P} = \frac{P}{V}$.Since $V$ is constant,$I \propto P$.Because $P_B > P_A$ $(100\, W > 60\, W)$,the current drawn by bulb $B$ is greater than the current drawn by bulb $A$ $(I_B > I_A)$.

Two electric bulbs $A$ and $B$ are rated as $60\, W$ and $100\, W$. They are connected in parallel to the same source. Then,

Similar Questions

In the circuit diagram,the heat produced in resistors $R$,$2R$,and $1.5R$ are in the ratio of:

$A\, 5\, ^oC$ rise in the temperature is observed in a conductor by passing some current. When the current is doubled,then the rise in temperature will be equal to ............. $^oC$.

$A$ constant voltage is applied between two ends of a metallic wire. If the length is halved and the radius of the wire is doubled,the rate of heat developed in the wire will be

$A$ current $i$ passes through a wire of length $l$, radius of cross-section $r$ and resistivity $\rho$. The rate of heat generation is

$A$ hot electric iron has a resistance of $80\,\Omega$ and is used on a $200\,V$ source. The electrical energy spent,if it is used for two hours,will be ........... $Wh$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module