Two equal resistances when connected in serie | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the value of each resistance be $R$ and the voltage of the battery be $V$. In series combination,the equivalent resistance is $R_s = R + R = 2

Vedclass · Accepted Answer

$240$

Vedclass · Answer

(B) Let the value of each resistance be $R$ and the voltage of the battery be $V$. In series combination,the equivalent resistance is $R_s = R + R = 2R$. The power consumed in series is $P_s = \frac{V^2}{R_s} = \frac{V^2}{2R} = 60 \ W$. From this,we get $\frac{V^2}{R} = 120 \ W$. In parallel combination,the equivalent resistance is $R_p = \frac{R 	imes R}{R + R} = \frac{R}{2}$. The power consumed in parallel is $P_p = \frac{V^2}{R_p} = \frac{V^2}{R/2} = 2 	imes \frac{V^2}{R}$. Substituting the value of $\frac{V^2}{R}$,we get $P_p = 2 	imes 120 = 240 \ W$.

Two equal resistances when connected in series to a battery,consume electric power of $60 \ W$. If these resistances are now connected in parallel combination to the same battery,the electric power consumed will be............. $W$

Similar Questions

If $m_1$ and $m_2$ $(m_1 > m_2)$ are the slopes of the lines represented by $5x^2 - 8xy + 3y^2 = 0$,then $m_1 : m_2$ equals

Which of the following hydrides is the least stable?

If $\alpha, \beta$ and $\gamma$ are the lengths of the altitudes of a $\triangle ABC$ with area $\Delta$,then $\frac{\Delta^2}{R^2}\left(\frac{1}{\alpha^2}+\frac{1}{\beta^2}+\frac{1}{\gamma^2}\right)$ is equal to

Due to low ionization energy,alkali metals are .......

The distance between the two parallel lines represented by $8x^2 - 24xy + 18y^2 - 6x + 9y - 5 = 0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module