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(A) Since the resistors are connected in parallel,the potential difference $(V)$ across each resistor is the same.Power consumed by a resistor is give

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$2: 1$

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(A) Since the resistors are connected in parallel,the potential difference $(V)$ across each resistor is the same.Power consumed by a resistor is given by the formula $P = \frac{V^2}{R}$.Since $V$ is constant for both resistors,we have $P \propto \frac{1}{R}$.Therefore,the ratio of power consumed is $\frac{P_1}{P_2} = \frac{R_2}{R_1}$.Given $R_1 = 10 \Omega$ and $R_2 = 20 \Omega$,we get:$\frac{P_1}{P_2} = \frac{20}{10} = \frac{2}{1}$.Thus,the ratio of power consumed by them is $2: 1$.

Two heating coils of resistances $10 \Omega$ and $20 \Omega$ are connected in parallel and connected to a battery of emf $12 \text{ V}$ and internal resistance $1 \Omega$. The ratio of the power consumed by them is:

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