Two ideal diodes are connected in the network as shown in the figure. The equivalent resistance between $A$ and $B$ is $.......\Omega$.

$A$ semiconductor device is connected in a series circuit with a battery and a resistance. $A$ current is found to pass through the circuit. If the polarity of the battery is reversed,the current drops almost to zero. The device may be

For the diagram shown,the resistances between points $A$ and $B$ when the ideal diode $D$ is forward biased is $R_1$ and when it is reverse biased is $R_2$. The ratio $R_1: R_2$ is

Consider a $p-n$ junction as a capacitor, formed with $p$ and $n$-materials acting as thin metal electrodes and depletion layer width acting as separation between them. Basing on this, assume that an $n-p-n$ transistor is working as an amplifier in $CE$ configuration. If $C_1$ and $C_2$ are the base-emitter and collector-emitter junction capacitances, then :

What is the current in the circuit shown below?

Can we take one slab of $p-$type semiconductor and physically join it to another $n-$type semiconductor to get $p-n$ junction?