Two identical bodies are made of a material f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the heat capacity of the bodies be $C(T)$,where $C(T)$ is an increasing function of temperature $T$.When the two bodies are brought into conta

Vedclass · Accepted Answer

more than $50^{\circ} C$

Vedclass · Answer

(D) Let the heat capacity of the bodies be $C(T)$,where $C(T)$ is an increasing function of temperature $T$.When the two bodies are brought into contact,heat flows from the hotter body $(100^{\circ} C)$ to the colder body $(0^{\circ} C)$ until they reach a common final temperature $T_f$.According to the principle of calorimetry,the heat lost by the hotter body equals the heat gained by the colder body:$\int_{T_f}^{100} C(T) dT = \int_{0}^{T_f} C(T) dT$.Since $C(T)$ increases with temperature,the heat capacity of the hotter body is higher than that of the colder body throughout the process of reaching equilibrium.Because the hotter body has a higher heat capacity,it requires more energy to change its temperature by a certain amount compared to the colder body.Therefore,the final equilibrium temperature $T_f$ will be closer to the initial temperature of the body with the higher heat capacity.Thus,$T_f > 50^{\circ} C$.

Similar Questions

$80\, g$ of water at $30^{\circ}C$ is poured on a large block of ice at $0^{\circ}C$. The mass of ice that melts is ........ $g$.

$2 \ kg$ of ice at $-20^{\circ} C$ is mixed with $5 \ kg$ of water at $20^{\circ} C$. The final mass of water formed is: (in $kg$)

$A$ metal ball of mass $100 \ g$ at $20^{\circ} C$ is dropped in $200 \ ml$ of water at $80^{\circ} C$. If the resultant temperature is $70^{\circ} C$,then the ratio of specific heat of the metal to that of water is

Vedclass Test Series

Exam Paper Generator

Online Exam Module