Two identical metallic square loops L_1 and L | vedclass

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(D) According to Lenz's Law,the induced current in loop $L_2$ will oppose the change in magnetic flux linked with it.As the current in loop $L_1$ incr

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moves away from $L_1$

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(D) According to Lenz's Law,the induced current in loop $L_2$ will oppose the change in magnetic flux linked with it.As the current in loop $L_1$ increases with time,the magnetic flux linked with loop $L_2$ also increases.To oppose this increase in flux,the induced current in loop $L_2$ flows in such a direction that the magnetic field produced by it opposes the magnetic field of $L_1$. This results in currents flowing in opposite directions in the adjacent arms of the two loops.Since currents in the adjacent arms of $L_1$ and $L_2$ are in opposite directions,there is a repulsive force between them.Consequently,loop $L_2$ moves away from loop $L_1$.

Two identical metallic square loops $L_1$ and $L_2$ are placed next to each other with their sides parallel on a smooth horizontal table. Loop $L_1$ is fixed and a current which increases as a function of time is passed through it. Then,loop $L_2$ is

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