Two identical photo-cathodes receive light of frequencies $f_1$ and $f_2$. If the velocities of the photoelectrons (of mass $m$) coming out are respectively $v_1$ and $v_2$,then:

  • A
    ${v_1} - {v_2} = {\left[ {\frac{{2h}}{m}\left( {{f_1} - {f_2}} \right)} \right]^{1/2}}$
  • B
    $v_1^2 - v_2^2 = \frac{{2h}}{m}\left( {{f_1} - {f_2}} \right)$
  • C
    ${v_1} + {v_2} = {\left[ {\frac{{2h}}{m}\left( {{f_1} + {f_2}} \right)} \right]^{1/2}}$
  • D
    $v_1^2 + v_2^2 = \frac{{2h}}{m}\left( {{f_1} + {f_2}} \right)$

Explore More

Similar Questions

$A$ body is projected with a speed $u \ m/s$ at an angle $\beta$ with the horizontal. The kinetic energy at the highest point is $\frac{3}{4}$ of the initial kinetic energy. The value of $\beta$ is $....^{\circ}$

$A$ vessel is filled with an ideal gas at a pressure of $10 \ atm$ and temperature $27^\circ C$. Half of the mass of the gas is removed from the vessel and the temperature of the remaining gas is increased to $87^\circ C$. Then the pressure of the gas in the vessel will be ...... $atm$.

Which one of the following compounds gives aspirin on reacting with acetic anhydride in the presence of conc. $H_2SO_4$?

$A$ ray of light strikes a plane mirror $M$ at an angle of $45^o$ as shown in the figure. After reflection,the ray passes through a prism of refractive index $1.5$ whose apex angle is $4^o$. The total angle through which the ray is deviated is....$^o$

If $\int \frac{dx}{(1+\sqrt{x}) \sqrt{x-x^2}} = \frac{A \sqrt{x}}{\sqrt{1-x}} + \frac{B}{\sqrt{1-x}} + C$,where $C$ is a real constant,then $A+B$ equals to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo