Two identical progressive waves moving in opposite directions superimpose to produce a stationary wave. The wavelength of each progressive wave is $\lambda$. The wavelength of the stationary wave is
- A$\frac{\lambda}{4}$
- B$\frac{\lambda}{2}$
- C$\lambda$
- D$2 \lambda$
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$A$ string fixed at both ends vibrates in a resonant mode with a separation of $2.0 \, cm$ between consecutive nodes. For the next higher resonant frequency,this separation is reduced to $1.6 \, cm$. The length of the string is .... $cm$.
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View SolutionStanding waves are produced in a $10 \; m$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20 \; m/s$,the frequency is ... $Hz$.
MediumAIIMS 1998
View SolutionGive the values of the amplitude at a node and an anti-node in a stationary wave.
Easy
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