Two identical thin bar magnets,each of length | vedclass

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(C) The magnetic moment of a single bar magnet is given by $M = m 	imes l$,where $m$ is the pole strength and $l$ is the length of the magnet.Since t

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$\sqrt{2}\,ml$

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(C) The magnetic moment of a single bar magnet is given by $M = m 	imes l$,where $m$ is the pole strength and $l$ is the length of the magnet.Since the two magnets are identical and placed at a right angle to each other,their individual magnetic moment vectors $\vec{M_1}$ and $\vec{M_2}$ are also at a right angle to each other.The magnitude of each magnetic moment is $M = ml$.The net magnetic moment of the system is the vector sum of the two individual magnetic moments:$M_{net} = \sqrt{M_1^2 + M_2^2 + 2M_1M_2 \cos(90^\circ)}$Since $\cos(90^\circ) = 0$,we have:$M_{net} = \sqrt{M^2 + M^2} = \sqrt{2M^2} = \sqrt{2}M$Substituting $M = ml$,we get:$M_{net} = \sqrt{2}\,ml$.

Two identical thin bar magnets,each of length $l$ and pole strength $m$,are placed at a right angle to each other with the north pole of one touching the south pole of the other. The magnetic moment of the system is:

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