Two infinitely long parallel wires carry equa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the current in both wires be $I$ and the distance between them be $d$. The midpoint is at a distance $r = d/2$ from each wire.According to the

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(D) Let the current in both wires be $I$ and the distance between them be $d$. The midpoint is at a distance $r = d/2$ from each wire.According to the Right-Hand Thumb Rule,the magnetic field $B$ produced by an infinitely long wire at a distance $r$ is given by $B = \frac{\mu_0 I}{2\pi r}$.Since the currents are in the same direction,at the midpoint,the magnetic field due to the first wire points into the plane (or out of the plane depending on orientation),and the magnetic field due to the second wire points in the opposite direction.Since the currents $I$ and distances $r$ are equal for both wires,the magnitudes of the magnetic fields are equal: $B_1 = B_2 = \frac{\mu_0 I}{2\pi (d/2)}$.Because the vectors are equal in magnitude and opposite in direction,the net magnetic field $B_{Net} = B_1 - B_2 = 0$.

Two infinitely long parallel wires carry equal current in the same direction. The magnetic field at a midpoint between the two wires is

Similar Questions

Find the magnetic field at the point $P$ in the figure. The curved portion is a quarter-circle connected to two long straight wires.

$A$ particle carrying a charge equal to $100$ times the charge on an electron is rotating one rotation per second in a circular path of radius $0.8 \ m$. The value of magnetic field produced at the centre will be $(\mu_0 = \text{permeability of vacuum})$

$A$ loop carrying current $I$ has the shape of a regular polygon of $n$ sides. If $R$ is the distance from the centre to any vertex,then the magnitude of the magnetic induction vector $B$ at the centre of the loop is

The magnetic field at the centre of a circular coil of radius $r$ carrying current $I$ is $B_1$. The field at the centre of another coil of radius $2r$ carrying the same current $I$ is $B_2$. The ratio $\frac{B_1}{B_2}$ is

The ratio of the magnetic field at the center of a current-carrying circular coil of radius $R$ to the magnetic field at a distance of $3R$ from the center on its axis is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module