Two masses of 10 , kg and 20 , kg respectivel | vedclass

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(B) Let $F_s$ be the spring force acting on the masses.For the $10 \, kg$ mass,the only horizontal force acting is the spring force $F_s$ towards the

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$4$

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(B) Let $F_s$ be the spring force acting on the masses.For the $10 \, kg$ mass,the only horizontal force acting is the spring force $F_s$ towards the right.Using Newton's second law,$F_s = m_1 a_1 = 10 \, kg 	imes 12 \, m/s^2 = 120 \, N$.Now,for the $20 \, kg$ mass,the forces acting are the applied force of $200 \, N$ towards the right and the spring force $F_s$ of $120 \, N$ towards the left.Applying Newton's second law for the $20 \, kg$ mass:$F_{net} = F_{applied} - F_s = m_2 a_2$$200 \, N - 120 \, N = 20 \, kg 	imes a_2$$80 \, N = 20 \, kg 	imes a_2$$a_2 = \frac{80}{20} = 4 \, m/s^2$.Therefore,the acceleration of the $20 \, kg$ mass is $4 \, m/s^2$ towards the right.

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