Two moles of HBr are added to CH_3-C equiv CH | vedclass

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(A) The addition of $HBr$ to alkynes in the presence of peroxide follows the anti-Markovnikov rule.First,$CH_3-C \equiv CH + HBr \xrightarrow{	ext{pe

Vedclass · Accepted Answer

$CH_3-CH_2-CHBr_2$

Vedclass · Answer

(A) The addition of $HBr$ to alkynes in the presence of peroxide follows the anti-Markovnikov rule.First,$CH_3-C \equiv CH + HBr \xrightarrow{	ext{peroxide}} CH_3-CH=CHBr$ ($1$-bromopropene).Second,the addition of another mole of $HBr$ to $CH_3-CH=CHBr$ in the presence of peroxide follows the anti-Markovnikov rule again,leading to the terminal dibromide.$CH_3-CH=CHBr + HBr \xrightarrow{	ext{peroxide}} CH_3-CH_2-CHBr_2$ ($1$,$1$-dibromopropane).Therefore,the final product is $CH_3-CH_2-CHBr_2$.

Two moles of $HBr$ are added to $CH_3-C \equiv CH$ in the presence of peroxide to give:

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