Two numbers are chosen at random from {1, 2, | vedclass

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(C) Total number of ways to choose $2$ numbers from $8$ is ${}^8C_2 = \frac{8 	imes 7}{2} = 28$. Let the two numbers be $x$ and $y$ such that $x < y$

Vedclass · Accepted Answer

$\frac{9}{14}$

Vedclass · Answer

(C) Total number of ways to choose $2$ numbers from $8$ is ${}^8C_2 = \frac{8 	imes 7}{2} = 28$. Let the two numbers be $x$ and $y$ such that $x Case $I$: If $x = 1$,then $y$ can be any of the remaining $7$ numbers $\{2, 3, 4, 5, 6, 7, 8\}$. Number of ways $= 7$. Case $II$: If $x = 2$,then $y$ can be any of the remaining $6$ numbers $\{3, 4, 5, 6, 7, 8\}$. Number of ways $= 6$. Case $III$: If $x = 3$,then $y$ can be any of the remaining $5$ numbers $\{4, 5, 6, 7, 8\}$. Number of ways $= 5$. Total favorable cases $= 7 + 6 + 5 = 18$. Required probability $= \frac{18}{28} = \frac{9}{14}$.

Column-$I$	Column-$II$
$(a)$ Parturition	$(p)$ Attachment of embryo to endometrium
$(b)$ Gestation	$(q)$ Release of egg from Graafian follicle
$(c)$ Ovulation	$(r)$ Delivery of Foetus from uterus
$(d)$ Implantation	$(s)$ Duration between pregnancy and birth
	$(t)$ Formation of zygote by fusion of egg and sperm

Two numbers are chosen at random from $\{1, 2, 3, 4, 5, 6, 7, 8\}$ at a time. The probability that the smaller of the two numbers is less than $4$ is

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