Two numbers are in the ratio 3:4. Their L.C.M | vedclass

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(C) Let the two numbers be $3x$ and $4x$,where $x$ is the common factor.The prime factorization of the numbers is:$3x = 3 	imes x$$4x = 2^2 	imes x$

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(C) Let the two numbers be $3x$ and $4x$,where $x$ is the common factor.The prime factorization of the numbers is:$3x = 3 	imes x$$4x = 2^2 	imes x$The $L.C.M.$ of $3x$ and $4x$ is $3 	imes 2^2 	imes x = 12x$.Given that the $L.C.M.$ is $84$,we set up the equation:$12x = 84$Solving for $x$:$x = 84 / 12 = 7$Now,calculate the two numbers:First number $= 3x = 3 	imes 7 = 21$Second number $= 4x = 4 	imes 7 = 28$Comparing the two numbers,$21$ and $28$,the greater number is $28$.

Two numbers are in the ratio $3:4$. Their $L.C.M.$ is $84$. The greater number is

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