Two numbers are in the ratio 5:6. If 8 is sub | vedclass

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(D) Let the two numbers be $5x$ and $6x$ based on the given ratio $5:6$.According to the second condition,if $8$ is subtracted from each number,the ra

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$40$ and $48$

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(D) Let the two numbers be $5x$ and $6x$ based on the given ratio $5:6$.According to the second condition,if $8$ is subtracted from each number,the ratio becomes $4:5$.So,$\frac{5x - 8}{6x - 8} = \frac{4}{5}$.Cross-multiplying,we get $5(5x - 8) = 4(6x - 8)$.$25x - 40 = 24x - 32$.$25x - 24x = 40 - 32$.$x = 8$.Therefore,the first number is $5x = 5 	imes 8 = 40$.The second number is $6x = 6 	imes 8 = 48$.Thus,the required numbers are $40$ and $48$.

Two numbers are in the ratio $5:6$. If $8$ is subtracted from each of the numbers,the ratio becomes $4:5$. Find the numbers.

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