Two point charges Q and -3Q are placed at a d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the charges be at points $A$ and $B$ separated by distance $x$. The electric field at $A$ (location of $Q$) is due to the charge $-3Q$ at $B$.

Vedclass · Accepted Answer

$E/3$

Vedclass · Answer

(D) Let the charges be at points $A$ and $B$ separated by distance $x$. The electric field at $A$ (location of $Q$) is due to the charge $-3Q$ at $B$.$E = \frac{k| -3Q |}{x^2} = \frac{3kQ}{x^2}$.Now,the electric field at $B$ (location of $-3Q$) is due to the charge $Q$ at $A$.$E' = \frac{k|Q|}{x^2} = \frac{kQ}{x^2}$.Comparing the two expressions,we get $E' = \frac{E}{3}$.Since both fields are directed along the line $AB$ (the field at $A$ is towards $B$ and the field at $B$ is away from $A$),the magnitude is $E/3$.

Two point charges $Q$ and $-3Q$ are placed at a distance $x$ apart. If the electric field at the location of $Q$ is $E$,then the electric field at the location of $-3Q$ is:

Similar Questions

Explain electric field and its source as well as magnetic field and its source.

In the given figure,the electric field at the center $O$ due to section $AB$ of a uniformly charged ring is $\overrightarrow{E}$. What will be the electric field at $O$ due to the remaining section $ACB$?

$A$ charge of $1 \mu C$ each is placed on five corners of a regular hexagon of side $1 \ m$. The electric field at its centre is . . . . . . $N$/$C$.

$A$ spherical conductor of radius $12 \;cm$ has a charge of $1.6 \times 10^{-7} \;C$ distributed uniformly on its surface. What is the electric field
$(a)$ inside the sphere
$(b)$ just outside the sphere
$(c)$ at a point $18\; cm$ from the centre of the sphere?

Three charges $2q, -q, -q$ are located at the vertices of an equilateral triangle. At the centre of the triangle:

Vedclass Test Series

Exam Paper Generator

Online Exam Module