Two resistance wires on joining in parallel t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the resistances of the two wires be $R_1$ and $R_2$.When connected in parallel,the equivalent resistance $R_p$ is given by $\frac{1}{R_p} = \f

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(D) Let the resistances of the two wires be $R_1$ and $R_2$.When connected in parallel,the equivalent resistance $R_p$ is given by $\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2}$,which implies $R_p = \frac{R_1 R_2}{R_1 + R_2}$.Given $R_p = \frac{6}{5} \ \Omega$,we have $\frac{R_1 R_2}{R_1 + R_2} = \frac{6}{5}$.If one wire breaks,the effective resistance becomes the resistance of the remaining wire. Let $R_1 = 2 \ \Omega$.Substituting $R_1 = 2$ into the parallel equation:$\frac{2 R_2}{2 + R_2} = \frac{6}{5}$$10 R_2 = 6(2 + R_2)$$10 R_2 = 12 + 6 R_2$$4 R_2 = 12$$R_2 = 3 \ \Omega$.Thus,the resistance of the broken wire is $3 \ \Omega$.

Two resistance wires on joining in parallel the resultant resistance is $\frac{6}{5} \ \Omega$. One of the wires breaks,the effective resistance is $2 \ \Omega$. The resistance of the broken wire is ............ $\Omega$.

Similar Questions

Find the equivalent resistance between point $A$ and $B$ in the following circuit. (The resistance of each resistor is $R$)

Two resistances are joined in parallel whose resultant is $6/8 \, \Omega$. One of the resistance wires is broken and the effective resistance becomes $2 \, \Omega$. Then the resistance in ohm of the wire that got broken was:

Six equal resistances are connected between points $P, Q$ and $R$ as shown in the figure. Then the net resistance will be maximum between:

In this circuit,the value of $I_2$ is (in $A$)

Two bulbs of $100\, W$ and $200\, W$ working at $220\, V$ are joined in series with a $220\, V$ supply. The total power consumed will be approximately ........... $W$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module