Two rods,one of aluminium and the other of st | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The change in length of a rod due to thermal expansion is given by $\Delta L = L \alpha \Delta T$.Given that the change in length for both rods is

Vedclass · Accepted Answer

$\frac{\alpha_2}{(\alpha_1+\alpha_2)}$

Vedclass · Answer

(C) The change in length of a rod due to thermal expansion is given by $\Delta L = L \alpha \Delta T$.Given that the change in length for both rods is the same,we have $\Delta L_1 = \Delta L_2$.Substituting the formula,we get $L_1 \alpha_1 t = L_2 \alpha_2 t$.Canceling $t$ from both sides,we get $L_1 \alpha_1 = L_2 \alpha_2$,which implies $\frac{L_1}{L_2} = \frac{\alpha_2}{\alpha_1}$.To find the ratio $\frac{L_1}{L_1+L_2}$,we use the property of ratios: if $\frac{a}{b} = \frac{c}{d}$,then $\frac{a}{a+b} = \frac{c}{c+d}$.Applying this to our equation,we get $\frac{L_1}{L_1+L_2} = \frac{\alpha_2}{\alpha_1+\alpha_2}$.

Similar Questions

The coefficient of superficial expansion of a solid is $2 \times 10^{-5} \text{ °C}^{-1}$. Its coefficient of linear expansion is:

The density of a substance at $0^{\circ}C$ is $10 \, g/cm^3$ and at $100^{\circ}C$,its density is $9.7 \, g/cm^3$. The coefficient of linear expansion of the substance is:

Two large holes are cut in a metal sheet. If this sheet is heated,what happens to the distances $AB$ and $BC$ as shown in the figure?

When a copper ball is heated,the largest percentage increase will occur in its

Vedclass Test Series

Exam Paper Generator

Online Exam Module