Two solenoids of equal number of turns have t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The self-inductance $L$ of a solenoid is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $N$ is the number of turns,$A = \pi r^2$ is the cr

Vedclass · Accepted Answer

$1: 3$

Vedclass · Answer

(A) The self-inductance $L$ of a solenoid is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $N$ is the number of turns,$A = \pi r^2$ is the cross-sectional area,and $l$ is the length of the solenoid.Since $N$ is constant for both solenoids,we have $L \propto \frac{r^2}{l}$.Given the ratio of lengths $l_1 : l_2 = 1 : 3$ and radii $r_1 : r_2 = 1 : 3$.Substituting these values into the ratio:$\frac{L_1}{L_2} = \left( \frac{r_1}{r_2} ight)^2 	imes \left( \frac{l_2}{l_1} ight)$$\frac{L_1}{L_2} = \left( \frac{1}{3} ight)^2 	imes \left( \frac{3}{1} ight)$$\frac{L_1}{L_2} = \frac{1}{9} 	imes 3 = \frac{1}{3}$.Therefore,the ratio of their self-inductance is $1: 3$.

Two solenoids of equal number of turns have their lengths as well as radii in the same ratio $1: 3$. The ratio of their self-inductance will be

Similar Questions

When the current through a solenoid increases at a constant rate, the induced current

The $SI$ unit of self-inductance is:

When current in a coil changes from $5\,A$ to $2\,A$ in $0.1\,s,$ an average voltage of $50\,V$ is produced. The self-inductance of the coil is.......$H$.

The adjoining figure shows two bulbs $B_1$ and $B_2$,a resistor $R$,and an inductor $L$. When the switch $S$ is turned off,what happens to the bulbs?

Vedclass Test Series

Exam Paper Generator

Online Exam Module