Two stones having different masses m_1 and m_ | vedclass

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(D) The maximum height $H$ attained by a projectile is given by the formula $H = \frac{u^2 \sin^2 	heta}{2g}$,where $u$ is the initial speed,$	heta$

Vedclass · Accepted Answer

$	an^2 \alpha: 1$

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(D) The maximum height $H$ attained by a projectile is given by the formula $H = \frac{u^2 \sin^2 	heta}{2g}$,where $u$ is the initial speed,$	heta$ is the angle of projection,and $g$ is the acceleration due to gravity.For the first stone,the angle of projection is $\alpha$,so its maximum height is $H_1 = \frac{u^2 \sin^2 \alpha}{2g}$.For the second stone,the angle of projection is $(90^{\circ}-\alpha)$,so its maximum height is $H_2 = \frac{u^2 \sin^2(90^{\circ}-\alpha)}{2g}$.Since $\sin(90^{\circ}-\alpha) = \cos \alpha$,we have $H_2 = \frac{u^2 \cos^2 \alpha}{2g}$.The ratio of their maximum heights is $\frac{H_1}{H_2} = \frac{\frac{u^2 \sin^2 \alpha}{2g}}{\frac{u^2 \cos^2 \alpha}{2g}} = \frac{\sin^2 \alpha}{\cos^2 \alpha} = 	an^2 \alpha$.Thus,the ratio is $	an^2 \alpha : 1$.

Two stones having different masses $m_1$ and $m_2$ are projected at an angle $\alpha$ and $(90^{\circ}-\alpha)$ with the same speed from the same point. The ratio of their maximum heights is

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