Two straight paths are represented by the equ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given linear equations are:$x-3y-2=0$ ..... $(i)$$-2x+6y-5=0$ ..... $(ii)$Comparing these equations with the general form $ax+by+c=0$,we get:F

Vedclass · Accepted Answer

No,they do not cross each other.

Vedclass · Answer

(B) The given linear equations are:$x-3y-2=0$ ..... $(i)$$-2x+6y-5=0$ ..... $(ii)$Comparing these equations with the general form $ax+by+c=0$,we get:For equation $(i)$: $a_1=1, b_1=-3, c_1=-2$For equation $(ii)$: $a_2=-2, b_2=6, c_2=-5$Now,calculating the ratios:$\frac{a_1}{a_2} = \frac{1}{-2} = -\frac{1}{2}$$\frac{b_1}{b_2} = \frac{-3}{6} = -\frac{1}{2}$$\frac{c_1}{c_2} = \frac{-2}{-5} = \frac{2}{5}$Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines are parallel.Therefore,the two straight paths represented by the given equations never cross each other.

Two straight paths are represented by the equations $x-3y=2$ and $-2x+6y=5$. Check whether the paths cross each other or not.

Similar Questions

The standard form of the equation $5y = -2x + 3$ is........

Find the value of $k$ for which the following pair of linear equations has infinitely many solutions:
$kx + 3y = k - 3$
$12x + ky = k$

The solution set of a pair of equations $5x - 5y = -5$ and $\frac{3x}{2} - \frac{3y}{2} + \frac{3}{2} = 0$ is.........

The pair of equations $ax - y = 5$ and $4x - 2y = 10$ has an infinite number of solutions. Then $a = \ldots$

The graph of the equation $\ldots \ldots \ldots \ldots$ is a line perpendicular to the $X$-axis.

Vedclass Test Series

Exam Paper Generator

Online Exam Module