Two trains of equal length take 10 , s and 15 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Speed of the first train $(S_1) = \frac{120 \, m}{10 \, s} = 12 \, m/s$.Speed of the second train $(S_2) = \frac{120 \, m}{15 \, s} = 8 \, m/s$.Wh

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(D) Speed of the first train $(S_1) = \frac{120 \, m}{10 \, s} = 12 \, m/s$.Speed of the second train $(S_2) = \frac{120 \, m}{15 \, s} = 8 \, m/s$.When travelling in the same direction,the relative speed is $(S_1 - S_2) = 12 - 8 = 4 \, m/s$.To cross each other,the total distance to be covered is the sum of the lengths of both trains: $120 \, m + 120 \, m = 240 \, m$.Required time $= \frac{	ext{Total Distance}}{	ext{Relative Speed}} = \frac{240 \, m}{4 \, m/s} = 60 \, s$.

Two trains of equal length take $10 \, s$ and $15 \, s$ respectively to cross a telegraph post. If the length of each train is $120 \, m$,in what time (in $s$) will they cross each other while travelling in the same direction?

Similar Questions

$A$ man travels a distance of $24 \, km$ at $6 \, km/h$,another distance of $24 \, km$ at $8 \, km/h$,and a third distance of $24 \, km$ at $12 \, km/h$. His average speed for the whole journey (in $km/h$) is?

$A$ $135\, m$ long train is running with a speed of $54\, km/h$. In what time will it pass a telegraph post? (in $seconds$)

$A$ person crosses a $600\, m$ long street in $5\, minutes$. What is his speed in $km/hr$?

$A$ train takes $18 \, s$ to pass completely through a station $162 \, m$ long and $15 \, s$ through another station $120 \, m$ long. The length of the train (in $m$) is:

If a person walks at $14 \, km/hr$ instead of $10 \, km/hr$,he would have walked $20 \, km$ more. The actual distance travelled by him is (in $km$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module