Two very long straight wires are set parallel | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field due to a long straight wire carrying current $I$ at a distance $d$ is given by $B = \frac{\mu_0 I}{2 \pi d}$.For point $P$,the

Vedclass · Accepted Answer

$\frac{2}{3} \frac{\mu_0 I}{\pi r}$

Vedclass · Answer

(C) The magnetic field due to a long straight wire carrying current $I$ at a distance $d$ is given by $B = \frac{\mu_0 I}{2 \pi d}$.For point $P$,the distance from wire $1$ is $r$. Thus,the magnetic field due to wire $1$ is $B_1 = \frac{\mu_0 I}{2 \pi r}$ (directed into the page).The distance from wire $2$ is $2r + r = 3r$. Thus,the magnetic field due to wire $2$ is $B_2 = \frac{\mu_0 I}{2 \pi (3r)} = \frac{\mu_0 I}{6 \pi r}$ (directed into the page).Since both fields are in the same direction (into the page),the net magnetic field $B_{net}$ is:$B_{net} = B_1 + B_2$$B_{net} = \frac{\mu_0 I}{2 \pi r} + \frac{\mu_0 I}{6 \pi r}$$B_{net} = \frac{\mu_0 I}{2 \pi r} (1 + \frac{1}{3}) = \frac{\mu_0 I}{2 \pi r} (\frac{4}{3}) = \frac{2 \mu_0 I}{3 \pi r}$.

Two very long straight wires are set parallel to each other. Each carries a current $I$ in the same direction and the separation between them is $2r$. The intensity of the magnetic field at point $P$ as shown in the figure is . . . . . . .

Similar Questions

$A$ long wire carries a steady current. It is bent into a coil of one turn such that the magnetic induction at the centre is $B$. If the same wire is bent to form a coil of smaller radius with $n$ turns,then the new magnetic induction $B^{\prime}$ at the centre is:

An equilateral triangle of side '$a$' carries a current '$i$'. What is the magnetic field at point '$P$' (a vertex of the triangle)?

Two identical circular current loops of radius $R$ carrying equal currents $I$ are placed such that their axes are inclined at $45^\circ$ to each other. The distance from the center of each loop to point $P$ is $\sqrt{3}R$. The resultant magnetic field at $P$ is:

The radius of a circular coil is $R$ and it carries a current of $I$ ampere. The intensity of the magnetic field at a distance $x$ on the axis from the centre $(x >> R)$ will be:

$A$ loop carrying current $I$ has the shape of a regular polygon of $n$ sides. If $R$ is the distance from the centre to any vertex,then the magnitude of the magnetic induction vector $B$ at the centre of the loop is

Vedclass Test Series

Exam Paper Generator

Online Exam Module