Two waves having same intensity I_{0} and ori | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The resultant intensity $I$ of two superposing waves is given by the formula: $I = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}} \cos \phi$. For non-coherent

Vedclass · Accepted Answer

$2 I_{0}$

Vedclass · Answer

(C) The resultant intensity $I$ of two superposing waves is given by the formula: $I = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}} \cos \phi$. For non-coherent sources,the phase difference $\phi$ changes randomly with time. Therefore,the average value of the interference term $\langle 2\sqrt{I_{1}I_{2}} \cos \phi \rangle$ over time is $0$ because the average value of $\cos \phi$ is $0$. Given that $I_{1} = I_{2} = I_{0}$,the resultant average intensity is: $I_{avg} = I_{1} + I_{2} = I_{0} + I_{0} = 2I_{0}$.

Two waves having same intensity $I_{0}$ and originated from two non-coherent sources superpose at a point. The average intensity at that point is . . . . . . .

Similar Questions

Two waves having amplitudes in the ratio $5:1$ produce interference. The ratio of the maximum to minimum intensity is

Coherent sources are characterized by the same

In the phenomenon of interference:

The light beams of intensities in the ratio of $9: 1$ are allowed to interfere. What will be the ratio of the intensities of maxima and minima?

Vedclass Test Series

Exam Paper Generator

Online Exam Module